f(x)=x(x-2)^2/3 求导化简求具体过程!
问题描述:
f(x)=x(x-2)^2/3 求导化简求具体过程!
答
f'(x)=(x/3)'(x-2)^2+(x/3)[(x-2)^2]'
=(x-2)^2/3+(x/3)(2x-4)
=(x^2-4x+4)/3+(2x^2-4x)/3
=(3x^2-8x+4)/3
=(3x-2)(x-2)/3不是的,2/3是平方就是x(x-2) 的2/3次方- -括号写清楚啊不好意思阿帮我化简一下吧f(x)=(x^2-2x)^(2/3) f'(x)={2/[3(x^2-2x)^(1/3)]}*(x^2-2x)' = 4(x-1)/{3[x(x-2)]^(1/3)}谢谢你,但是恐怕不对吧哪里不对?