f(sinx)=3-cos 2x,则f(cos x)=?

问题描述:

f(sinx)=3-cos 2x,则f(cos x)=?
A.3-cos 2x B.3-sin2x C.3+cos2x D.3+sin2x

因为cos2x=1-2sin^2 x
f(sinx)=3-cos 2x=3-1+2sin^2 x=2+2sin^2x
所以
f(cosx)=2+2cos^2 x=2+cos2x+1=3+cos2x
选C