已知(x)=[sin(π-x)cos(2π-x)tan(-x+π)]/[cos(-π/2+x)]
问题描述:
已知(x)=[sin(π-x)cos(2π-x)tan(-x+π)]/[cos(-π/2+x)]
答
-cosxtanx根据上题求f(-31π/3)的值上面的答案可化简为-sinxf(-31π/3)=f(-π/3)=-1/2
已知(x)=[sin(π-x)cos(2π-x)tan(-x+π)]/[cos(-π/2+x)]
-cosxtanx根据上题求f(-31π/3)的值上面的答案可化简为-sinxf(-31π/3)=f(-π/3)=-1/2