计算x=? √(50-(x/2)^2+√(10-(x/2)^2=√20
问题描述：
计算x=? √(50-(x/2)^2+√(10-(x/2)^2=√20
式子右边是根号20啊
答
√(50-(x/2)^2+√(10-(x/2)^2=√20√(50-(x/2)^2=√20-√(10-(x/2)^2两边平方50-(x/2)^2=20-2√[200-20(x/2)^2]+10-(x/2)^2√[200-20(x/2)^2]=-10两边平方200-20(x/2)^2=100(x/2)^2=5带入方程的√45+√5=√20显然不...