当x>1时,求y=2x+8/(x-1)最小值
问题描述:
当x>1时,求y=2x+8/(x-1)最小值
答
x>1
x-1>0
y=2x+8/(x-1)
=2+2(x-1)+8/(x-1)>=2+8=10
y=2x+8/(x-1)最小值是10