先化简,再求值:(x+1/x2−1+x/x−1)÷x+1/x2−2x+1,其中x=2.

问题描述:

先化简,再求值:(

x+1
x2−1
+
x
x−1
)÷
x+1
x2−2x+1
,其中x=2.

x+1
x2−1
+
x
x−1
)÷
x+1
x2−2x+1

=(
1
x−1
+
x
x−1
)•
(x−1)2
x+1

=
x+1
x−1
(x−1)2
x+1

=x-1,
当x=2时,运算=2-1=1.