若函数f(x,y)在矩形区域D:0
问题描述:
若函数f(x,y)在矩形区域D:0
数学人气:189 ℃时间:2020-02-06 00:04:32
优质解答
note that ∫∫f(x,y)dxdy is a constant,let it be c,thenxy*c^2=f(x,y)-1f(x,y)=xy*c^2+1,take the integral,we get∫∫f(x,y)dxdy=(c^2)/4+1but as assumed,it equals c.solve:(c^2)/4+1=c we get c=2thus,f(x,y)...
我来回答
类似推荐
- f(x,y)为连续函数且f(x,y)=xy+∫D∫f(u,v)dб,D:y=0,y=x的平方x=1所围闭区证明:∫D∫f(x,y)dxdy=1/8
- 函数f(x)当x>0有意义,且满足条件f(2)=1,f(xy)=f(x)+f(Y),f(x)是增函数,若F(3)+f(4-8x)>2,求x的取值范围
- 设f(x)是定义在(0,+∞)上的增函数,且f(xy)=f(x)+f(y),若f(3)=1且f(a)>f(a-1)+2,求实数a的取值范围.
- 函数f(x)对于x〉0有意义,且满足条件f(2)=1.f(xy)=f(x)+f(y).f(x)+f(x—3)》2成立,求x的取值范围
- 已知函数f(x)是定义在()上的减函数,且满足f(xy)=f(x)+f(y),f(1/3)=1.f(1)=0,若f(x)+F(2-x)
答
note that ∫∫f(x,y)dxdy is a constant,let it be c,thenxy*c^2=f(x,y)-1f(x,y)=xy*c^2+1,take the integral,we get∫∫f(x,y)dxdy=(c^2)/4+1but as assumed,it equals c.solve:(c^2)/4+1=c we get c=2thus,f(x,y)...