化简asin0°+bcos90°+ctan180°
问题描述：
化简asin0°+bcos90°+ctan180°
化简-P²cos180°+q²sin90°+2pqcos0°
答
sin0°=cos90°=tan180°=0
asin0°+bcos90°+ctan180°=0
cos180°=-1
sin90°=cos0°=1
-p²cos180°+q²sin90°+2pqcos0°
=p²+q²+2pq
=(p+q)²