化简:(1)asin0°+bsin90°+ctan180° (2)mtan0+ncos1/2×π-psinπ-qcos3/2×π-rsin2π
问题描述:
化简:(1)asin0°+bsin90°+ctan180° (2)mtan0+ncos1/2×π-psinπ-qcos3/2×π-rsin2π
答
(1)
asin0°+bsin90°+ctan180°
=a*0+b+c*0
=b
(2)
mtan0+ncos1/2×π-psinπ-qcos3/2×π-rsin2π
=m*0+n*0-p*0-(-q)-r*0
=q