[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
问题描述:
[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
数学:[2x²-(x+y) (x-y)] [(-x-y) (y-x)+2y²] 其中x=1,y=2
答