因式分解(x²+x+1)(x²-6x+1)+12x²
问题描述:
因式分解(x²+x+1)(x²-6x+1)+12x²
答
原式=(x+1)(6x^2+12x)-(x+1)-4x(x+2)-1
=6x(x+1)(x+2)-4x(x+2)-(x+2)
=(x+2)(6x^2+6x-4x-1)
=(x+2)(6x^2+2x-1)
7月E5
答
(x²+x+1)(x²-6x+1)+12x²
=(x^2+1)^2-5x(x^2+1)-6x^2+12x^2
=(x^2+1)^2-5x(x^2+1)+6x^2
=(x^2-2x+1)(x²-3x+1)
=(x-1)^2(x^2-3x+1)