计算:[(x-y)2+3(x2-1/3y2)]÷2x.

问题描述:

计算:[(x-y)2+3(x2-

1
3
y2)]÷2x.

原式=(x2-2xy+y2+3x2-y2)÷2x(3分);
=(4x2-2xy)÷2x(2分);
=2x-y(1分).