(2-3×5-1)+(4-3×5-2)+…(2n-3×5-n)=_.

问题描述:

(2-3×5-1)+(4-3×5-2)+…(2n-3×5-n)=______.

原式=(2+4+…+2n)-3×(5-1+5-2+…+5-n
=

n(2+2n)
2
-3×
5−1(1−5−n)
1−5−1

=n(n+1)-3×
1−5−n
4

=n(n+1)-
3
4
[1-(
1
5
)n
].
故答案为:n(n+1)-
3
4
[1-(
1
5
)n
].