解方程组4x^2/(1+4x^2)=y,4y^2/(1+4y^2)=z,4z^2/(1+4z^2)=x今晚要
问题描述：
解方程组4x^2/(1+4x^2)=y,4y^2/(1+4y^2)=z,4z^2/(1+4z^2)=x
今晚要
答
得到两组解
0,0,0
0.2119268995,0.2119268995,0.2119268995