关于微积分的数学题我不知道积分号怎么写,只能用f(t,0)表示了,即t到0的定积分,大家凑合看下a(t)=e^[f(t,0)0.1/(1+0.1r)dr]答案是推出a(t)=1+0.1t 有点怀疑答案,所以想证实下,

a(t)=e^[f(t,0)0.1/(1+0.1r)dr]
a(t)=e^ln(1+0.1r)t,0)(t,0)
a(t)=e^ln(1+0.1t)-e^ln(1+0.1*0)
a(t)=1+0.1t

对的
∫0.1dr/(1+0.1r)dr
=∫d0.1r/(1+0.1r)dr
=∫d(1+0.1r)/(1+0.1r)dr
=ln(1+0.1r)(t到0)
=ln(1+0.1t)-ln1
=ln(1+0.1t)
所以a(t)=e^[ln(1+0.1t)]=1+0.1t