初二4道因式分解题,求解!(1)4/9p²q²-1(2)25(m+n)²-9n²(3)4a³-4a²+a(4)(x-1)(x-3)+1请附上至少一步的过程,万分感谢!

问题描述:

初二4道因式分解题,求解!
(1)4/9p²q²-1
(2)25(m+n)²-9n²
(3)4a³-4a²+a
(4)(x-1)(x-3)+1
请附上至少一步的过程,万分感谢!

1.=(2/3pq)^2-1
=(2/3pq-1)(2/3pq+1)
2.=[5(m+n)]^2-(3n)^2
=(5m+5n+3n)(5m+5n-3n)
=(5m+8n)(5m+2n)
3.=a(4a^2-4a+1)
=a(2a-1)^2
4=x^2-4x+3+1
=x^2-4x+4
=(x-2)^2

1)4/9p²q²-1=(2/3pq-1)(2/3pq+1)(2)25(m+n)²-9n²=[2(m+n)+3n][2(m+n)-3n]=(2m+2n+3n)(2m+2n-3n)=(2m+5n)(2m-n)(3)4a³-4a²+a=a(4a²-4a+1)=a(2a-1)²(4)(x-1)(x-3...