已知x+y=5 xy=1,求(x-y)²的值

问题描述:

已知x+y=5 xy=1,求(x-y)²的值

(x+y)²=x²+y²+2xy=25
(x-y)²=x²+y²-2xy
=x²+y²+2xy-4xy
=25-4
=21