(3√48-2√27)÷√3+√2÷(3-√3)√12-√1/2-(√1/8-√27)1/2√6÷4√1/12*(-2/3√3/2)

问题描述:

(3√48-2√27)÷√3+√2÷(3-√3)
√12-√1/2-(√1/8-√27)
1/2√6÷4√1/12*(-2/3√3/2)

(3√48-2√27)÷√3+√2÷(3-√3)=(12√3-6√3)÷√3+√2(3+√3)÷(9-3)=6√3÷√3+(3√2+√6)÷6=6+1/2√2+1/6√3√12-√1/2-(√1/8-√27)=2√3-1/2√2-1/4√2+3√3=5√3-3/4√21/2√6÷4√1/12*(-2...