（a+1分之a的2次方-a+1）除以a的2次方-1分之a
问题描述：
（a+1分之a的2次方-a+1）除以a的2次方-1分之a
答
=[a²/(a+1)-(a-1)(a+1)/(a+1)]×(a+1)(a-1)/a
=(a²-a²+1)/(a+1)×(a+1)(a-1)/a
=(a-1)/a
答
原式=[a²/(a+1)-(a-1)]×(a²-1)/a
=[a²-(a+1)(a-1)]/(a+1)×(a+1)(a-1)/a
=(a²-a²+1)/(a+1)×(a+1)(a-1)/a
=1/(a+1)×(a+1)(a-1)/a
=(a-1)/a