【提公因式法】练习解答⑴x(x-y)(a-b)-y(y-x)(b-a)本来想打很多题..可不会符号..
问题描述：
【提公因式法】练习解答
⑴x(x-y)(a-b)-y(y-x)(b-a)
本来想打很多题..
可不会符号..
答
x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(-x+y)(-a+b)
=x(x-y)(a-b)-y*-(x-y)*-(a-b)
=x(x-y)(a-b)-y(x-y)(a-b)
=(x-y)(x-y)(a-b)
=(a-b)乘以(x-y)的平方
答
x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(-x+y)(-a+b)
=x(x-y)(a-b)-y*-(x-y)*-(a-b)
=x(x-y)(a-b)-y(x-y)(a-b)
=(x-y)(x-y)(a-b)
答
x(x-y)(a-b)-y(y-x)(b-a)
=x(x-y)(a-b)-y(x-y)(a-b)
=(a-b)(x-y)^2
答
原式=x（x-y）（a-b）-y（x-y）（a-b）
=（x-y）^2（a-b）
答
原式=(a-b)(x-y)^2