X+2Y+3Z=18 X+4Y+3Z=24 Y=?
问题描述:
X+2Y+3Z=18 X+4Y+3Z=24 Y=?
答
y=3.由2式减1式得2y=6.由此得y=3
答
2式减1式,得2Y=6,得Y=3
X+2Y+3Z=18 X+4Y+3Z=24 Y=?
y=3.由2式减1式得2y=6.由此得y=3
2式减1式,得2Y=6,得Y=3