初三数学题(分式化简)化简:(2009a/a^2-2a+1)/[(1/a-1)+1]

问题描述:

初三数学题(分式化简)
化简:(2009a/a^2-2a+1)/[(1/a-1)+1]

(2009a/a^2-2a+1)/[(1/a-1)+1] =2009a/(a-1)^2/[(1+a-1)/(a-1)] =2009a/(a-1)^2*(a-1)/a =2009/(a-1)