4（t-3)平方-9（2t+1）平方=0
问题描述：
4（t-3)平方-9（2t+1）平方=0
答
4（t²-6t+9)-9(4t²+4t+1)=0
4t²-24t+36-36t²-36t-9=0
32t²+60t-27=0
(8t+3)(4t-9)=0
t=-3/8 t=9/4
答
4(t-3)^2- 9(2t-1)^2=0
4(t-3)^2 = 9(2t-1)^2
2(t-3)=3(2t-1) t1=-3/4
2(t-3)=-3(2t-1) t2=9/8