当x>1时,化简|x-1|+2|1-x|+|x|

问题描述:

当x>1时,化简|x-1|+2|1-x|+|x|

|x-1|+2|1-x|+|x|
=x-1+2(x-1)+x
=x-1+2x-2+x
=4x-3

因为x>1,所以|x-1|= x-1 ,
|1-x|=x-1 ,|x| = x
所以,|x-1|+2|1-x|+|x|
=x-1+2(x-1)+x
=x-1+2x-2+x
=4x-3