x+2分之x-2 - x的平方-4分之16=1他们的最简公分母是什么?

(x+2)分之(x-2) -( x的平方-4)分之16=1 ?
(x-2)/(x+2)-16/(x²-4)=1
(x-2)²/[(x-2)(x+2)]-16/(x²-4)=1
(x-2)²/(x²-4)-16/(x²-4)=1
(x-2)²-16=x²-4
x²-4x+4-16=x²-4
-4x=8
x=-2
x=-2时分母x+2=0,x²-4=0,所以方程无解;
如果(x+2)分之(x-2) +( x的平方-4)分之16=1 ?
(x-2)²/(x²-4)+16/(x²-4)=1
(x-2)²+16=x²-4
x²-4x+4+16=x²-4
-4x=-24
x=6

x-2/x+2-(x+2)(x-2)=1
方程两边同乘以(x+2)(x-2)
(x-2)^2-(x+2)(x-2)=(x+2)(x-2)
(x-2)^2-2(x+2)(x-2)=0
x^2-2x+12=0
x1=√13+1
x2=-√13-1

x+x/2-2-x^2-16/4=1
-x^2+3x/2-7=0
x^2-3x/2+7=0
(x-3/4)^2-(3/4)^2+7=0
(x-3/4)^2=7-9/16=103/16
x-3/4=±1/4√103
x=(3+√103)/4 或 x=(3-√103)/4