(1).(b/2a)的平方乘以a-b/1,再减去b/a除以4/b

问题描述:

(1).(b/2a)的平方乘以a-b/1,再减去b/a除以4/b

(b/2a)² *(a-b)-(b/a)/(4/b)
=(a-b)b²/(4a²)-b²/(4a)
=(a-b)b²/(4a²)-ab²/(4a²)
=[(a-b)b²-ab²]/(4a²)
=-b③/(4a²)
③表示3次方