已知a-b-3ab=0,求(2a-2b+3ab)分之(a-b-6ab)的值
问题描述：
已知a-b-3ab=0,求(2a-2b+3ab)分之(a-b-6ab)的值
答
∵a-b-3ab=0
∴a-b=3ab
∴(a-b-6ab)/(2a-2b+3ab)=[(a-b)-6ab]/[2(a-b)+3ab]=(3ab-6ab)/(2×3ab+3ab)=(-3ab)/9ab=-1/3
答
你好,小巷老梧桐
∵a-b-3ab=0
∴a-b=3ab
∴(a-b-6ab)/(2a-2b+3ab)
=[(a-b)-6ab)]/[2(a-b)+3ab]
=[3ab-6ab]/[6ab+3ab]
=(-3ab)/9ab
=-1/3