sin13π/6+cos13π/3-tan(-23π/4)=
问题描述：
sin13π/6+cos13π/3-tan(-23π/4)=
答
sin13π/6+cos13π/3-tan(-23π/4)
=sin(2π+π/6)+cos(4π+π/3)+tan(6π-π/4)
=sin(π/6)+cos(π/3)-tan(π/4)
=1/2+1/2-1
=0
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