f(x)=asin(πx+α)+bcos(πx+α) ,f(2000)=-1 f(2009)=

问题描述:

f(x)=asin(πx+α)+bcos(πx+α) ,f(2000)=-1 f(2009)=

f(2009)=asin(π+α)+bcos(π+α)=-(asinα+bcosα)=-f(2000)=1