f(x)=asin(πx+α)+bcos(πx+α) ,f(2000)=-1 f(2009)=
问题描述:
f(x)=asin(πx+α)+bcos(πx+α) ,f(2000)=-1 f(2009)=
答
f(2009)=asin(π+α)+bcos(π+α)=-(asinα+bcosα)=-f(2000)=1
f(x)=asin(πx+α)+bcos(πx+α) ,f(2000)=-1 f(2009)=
f(2009)=asin(π+α)+bcos(π+α)=-(asinα+bcosα)=-f(2000)=1