先化简,后求值 2(a+根号3)(a-根号3)-a(a-6)+6 a=根号2-1
问题描述:
先化简,后求值 2(a+根号3)(a-根号3)-a(a-6)+6 a=根号2-1
答
∵原式=2(a-3)-a+6a+6 =2a-6-a+6a+6 =a+6a ∴当a=根号2-1时,原式=a+6a =(根号2-1)-6×(根号2-1) = 3-2根号2-6根号2-6 =-3-4根号2
答
2(a+根号3)(a-根号3)-a(a-6)+6 =2(a-3)-a+6a+6 =2a-6-a+6a+6 =a+6a 当a=根号2-1时,原式=(根号2-1)+6(根号2-1) =2-2根号2+1+6根号2-6 =-3+4根号2