计算 (1)(−1/2)−1−23×0.125+(3−27−2012)0 (2)(−ab)2÷(2a25b)2•a/5b (3)m+2n/n−m+n/m−n−2n/n−m (4)(x/x−y−2y/x−y)•xy/x−2y÷(1/x+1/y
问题描述:
计算
(1)(−
)−1−23×0.125+(1 2
−2012)0
3
−27
(2)(
)2÷(−a b
)2•2a2
5b
a 5b
(3)
+m+2n n−m
−n m−n
2n n−m
(4)(
−x x−y
)•2y x−y
÷(xy x−2y
+1 x
). 1 y
答
(1)原式=-2+8×0.125+1=-2+1+1=0;(2)原式=a2b2÷4a425b2•a5b=a2b2•25b24a2•a5b=5a4b;(3)原式=m+2nn−m-nn−m-2nn−m=m+2n−n−2nn−m=m−nn−m=-1;(4)原式=x−2yx−y•xyx−2y÷x+yxy=x−2yx−y•xyx...