y=(x+1)(x+2)(x+3) 它的导数用复合函数做
问题描述：
y=(x+1)(x+2)(x+3) 它的导数用复合函数做
答
y=(x+1)(x+2)(x+3)
y'=(x+1)'(x+2)(x+3)+(x+1)(x+2)'(x+3)+(x+1)(x+2)(x+3)'
=(x+2)(x+3)+(x+1)(x+3)+(x+1)(x+2)
=(x²+5x+6)+(x²+4x+3)+(x²+3x+2)
=3x²+12x+11