求下列不定积分：∫dx/(x²√x)
问题描述：
求下列不定积分：∫dx/(x²√x)
答
=∫ x^(-5/2)dx
=-2/3∫dx^(-3/2)
=-2/3*x^(-3/2)+C∫(1-1/x²)*x^(3/4)dx
= ∫(x^2-1)/x^(5/4)dx
let x=t^4