已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求cos(α-β﹚帮帮忙啊!
问题描述:
已知0<β<π/4<α<3π/4,cos(π/4-α)=3/5,sina(3π/4+β)=5/13,求cos(α-β﹚帮帮忙啊!
答
因为0<β<π/4<α<3π/4所以-π/2<π/4-α<03π/4<3π/4+β<π因为cos(π/4-α)=3/5,sin(3π/4+β)=5/13所以sin(π/4-α)=-√[1-(3/5)^2]=-4/5cos(3π/4+β)=-√[1-(5/13)^2]=-12/13所以cos(α-β)=-cos[π-...