抛物线y=-x2-2x+m,若其顶点在x轴上,则m=_.
问题描述:
抛物线y=-x2-2x+m,若其顶点在x轴上,则m=______.
答
∵抛物线y=-x2-2x+m,若其顶点在x轴上,
∴
=0,解得m=-1.4×(−1)×m−(−2)2
4×(−1)
故答案为:-1.