求y等于cos^2(2x-π/3)的导数.

问题描述:

求y等于cos^2(2x-π/3)的导数.

y=cos²(2x-π/3)
=[cos(4x-2π/3)+1]/2
=(1/2)cos(4x-2π/3)+1/2
y'=-(1/2)sin(4x-2π/3)*4
=-2sin(4x-2π/3)