已知a+1分之a2-9=0,试计算a2-4a+4分之a-1加上a2-4分之a2-1的值
问题描述：
已知a+1分之a2-9=0,试计算a2-4a+4分之a-1加上a2-4分之a2-1的值
答
a2-4a+4分之a-1加上a2-4分之a2-1=(a-1)/(a-2)^2+(a-1)(a+1)/[(a+2)(a-2)]=[(a-1)(a+2)+(a-1)(a+1)(a-2)/[(a+2)(a-2)^2]=(a-1)(a+2+a^2-a-2)/[(a+2)(a-2)^2]=a^2(a-1)/[(a+2)(a-2)^2]a+1分之a2-9=0(a^2-9)/(a+1)=0a^2...