计算:(200+198+196+…+2)-(1+3+5+…+199)=_.

问题描述:

计算:(200+198+196+…+2)-(1+3+5+…+199)=______.

(200+198+196+…+2)-(1+3+5+…+199),
=[(2+200)×100÷2]-[=(1+199)×100÷2]
=[202×50]-[200×50]
=(202-200)×50,
=100.
故答案为:100.