解分式方程:1/(x+2) + 1/(x+7) = 1/(x+3) + 1/(x+6)
问题描述：
解分式方程:1/(x+2) + 1/(x+7) = 1/(x+3) + 1/(x+6)
答
通分
(x+7+x+2)/(x+2)(x+7)=(x+6+x+3)/(x+3)(x+6)
(2x+9)/(x^2-9x+14)-(2x+9)/(x^2+9x+18)=0
(2x+9)[1/(x^2-9x+14)-1/(x^2+9x+18)]=0
因为x^2-9x+14不等于x^2+9x+18
所以1/(x^2-9x+14)-1/(x^2+9x+18)不等于0
所以2x+9=0
x=-9/2
分式方程要检验
经检验
x=-9/2是方程的解