指数函数 (1/2)^(x-1)<3
问题描述:
指数函数 (1/2)^(x-1)<3
答
(1/2)^(x-1)<3=(1/2)^log(1/2) (3)
(1/2)^x递减
所以x-1>log(1/2) (3)
x>log(1/2) (3)+1
所以x>log(1/2) (3/2)