2log(b)x=log(a)x+log(c)x
问题描述：
2log(b)x=log(a)x+log(c)x
求证,c^2=(ac)^[log(a)b]
答
2log(b)x=log(a)x+log(c)x2lgx/lgb=lgx/lga+lgx/lgc把lgx约分2/lgb=1/lga+1/lgc=(lga+lgc)/(lgalgc)=lg(ac)/(lgalgc)(lgb)/2=lgalgc/lg(ac)lgb/lga=2lgc/lg(ac)=lgc^2/lg(ac)所以loga(b)=log(ac)c^2(ac)^loga(b)=(ac...