已知a.b满足b-a=-2014,求代数式【(a+b)(a-b)-(a-b)²-2b(b-a)】/(4b)的值
问题描述:
已知a.b满足b-a=-2014,求代数式【(a+b)(a-b)-(a-b)²-2b(b-a)】/(4b)的值
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答
【(a+b)(a-b)-(a-b)²-2b(b-a)】/(4b)
=(a²-b²-a²+2ab-b²-2b²+2ab)/(4b)
=(4ab-4b²)/(4b)
=a-b
b-a=-2014
原式
=-(-2014)
=2014