Sn=1/(2^2-1)+1/(4^2-1)+1/(6^2-1)+.+1/[(2n)^2-1]
问题描述：
Sn=1/(2^2-1)+1/(4^2-1)+1/(6^2-1)+.+1/[(2n)^2-1]
求和
答
Sn=1/(2^2-1)+1/(4^2-1)+1/(6^2-1)+.+1/[(2n)^2-1]
=1/(2+1)(2-1)+1/(4+1)(4-1)+1/(6+1)(6-1)+.+1/(2n+1)(2n-1)
=1/(3*1)+1/(5*3)+1/(7*5)+.+1/(2n+1)(2n-1)
因为1/(2n+1)(2n-1)=0.5*[1/(2n-1)-1/(2n+1)]
所以
Sn=0.5*[1-1/3+1/3-1/5+1/5-1/7+.+1/(2n-1)-1/(2n+1)]
=0.5*[1-1/(2n +1 )]
=n/(2n+1)