|1-x|+√9-6x+x²(1≤x≤3)化简

问题描述:

|1-x|+√9-6x+x²(1≤x≤3)化简

1-x≤0,3-x≥0
所以原式= |1-x|+√(3-x)²
=|1-x|+|3-x|
=x-1+3-x
=2