|1-x|+√9-6x+x²(1≤x≤3)化简
问题描述:
|1-x|+√9-6x+x²(1≤x≤3)化简
答
1-x≤0,3-x≥0
所以原式= |1-x|+√(3-x)²
=|1-x|+|3-x|
=x-1+3-x
=2