若(x+y-5)²+根号下x-y+1=0,求-4x+3y的算术平方根

问题描述:

若(x+y-5)²+根号下x-y+1=0,求-4x+3y的算术平方根

∵(x+y-5)²+√(x-y+1)=0
∴x+y-5=0,x-y+1=0得x=2,y=3
故√(-4x+3y)=√1=1