-(x+2)?^2+16(x-1)^2怎么做?

分类: 作业答案 • 2021-12-31 12:01:23

问题描述：

答

-(x+2)^2+16(x-1)^2
=16(x-1)^2-(x+2)^2
=[4(x-1)-(x+2)][4(x-1)+(x+2)]
=(4x-4-x-2)(4x-4+x+2)
=(3x-6)(5x-2)
=3(x-2)(5x-2)