已知(a+1)^2+|b+5|=0,求3a^2b-[2a^2b-(2ab-a^2b)-4a^2]-
问题描述:
已知(a+1)^2+|b+5|=0,求3a^2b-[2a^2b-(2ab-a^2b)-4a^2]-
ab的值
答
根据题意得
a+1=0
b+5=0
∴a=-1
b=-5
3a^2b-[2a^2b-(2ab-a^2b)-4a^2]-ab
=3a²b-2a²b+2ab-a²b+4a²-ab
=4a²+ab
=4+5
=9