a1=m2/4
问题描述：
a1=m2/4
an为等比数列,q=m/2
bn=anSn/n2
Tn=b1+b2```````bn
比较Tn与a1/2的大小
答
a1=m2/4an为等比数列,q=m/2an=a1*q^(n-1)=m^2/4*(m/2)^(n-1)=m^(n+1)/2^(n+1)Sn=a1*(q^n-1)/(q-1)=m^2/4*(m^2/4-1)/(m/2-1)=m^2/4*(m^2-4)/(2m-4)=m^2/4*(m+2)/2=m^2(m+2)/8bn=an*Sn/n^2=m^(n+1)/2^(n+1)*m^2(m+2)/8...