(2y+1)(2y-1)(4y的平方+1)怎么算?
问题描述：
(2y+1)(2y-1)(4y的平方+1)怎么算?
答
(2y+1)(2y-1)(4y的平方+1)
=(4y²-1)(4y²+1)
=16y的4次方-1