已知x/2=y/3=z/5,且2x+y-z=4,求式子x-3y+2z的值
问题描述:
已知x/2=y/3=z/5,且2x+y-z=4,求式子x-3y+2z的值
答
x/2=y/3=z/5=t
x=2t,y=3t,z=5t
2x+y-z=4
4t+3t-5t=4
2t=4
t=2
所以
x=4,y=6,z=10
x-3y+2z
=4-16+20
=8